m=12m^2-16m=0

Solution for m=12m^2-16m=0 equation:

m=12m^2-16m=0

We move all terms to the left:

m-(12m^2-16m)=0

We get rid of parentheses

-12m^2+m+16m=0

We add all the numbers together, and all the variables

-12m^2+17m=0

a = -12; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-12)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-12}=\frac{-34}{-24}
=1+5/12
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-12}=\frac{0}{-24}
=0
$